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資料庫名稱： Oracle
資料庫版本：18c
內容/問題描述：
大家好 請教一題query如何解？謝謝！
Display a RANKING of the managers based on how many employees report to
them- note that a rank of 1 means that the manager manages the greatest
number of employees.
我用的是：
select m.first_name, m.last_name, COUNT(*) as NUM_EMPLOYEE from
RITDB_employee e, RANK() over (partition by (select COUNT(*) as NUM_EMPLOYEE
from RITDB_employee e INNER JOIN RITDB_manager m ON e.manager=m.employee_id
group by m.first_name, m.last_name) AS RANK) WHERE rownum=1)
錯誤為wondows function are not allowed here
Thanks a lot!!