※ 引述《winnerken (ken)》之銘言：
: The mercury spectrum has a green line at 546nm,and an ultraviolet
: line at 365nm. what is the first order angular separation between
: the two spectral lines obtained with a diffraction grating with
: 10000 rulings/cm ?
: 不太清楚這題要問甚麼? 是光學的題目 還是近物?
根據光柵工式或(單縫公式)
bsinθ=(2k+1)λ/2
題目是要找兩個光各自在屏上做第一級暗紋的夾角
代K=0 λ=546nm 跟 365nm
10000 rulings/cm 要換成 b = 10^(-6)
↑指這個光柵每公分有10000條狹縫
把它倒數後 再換成公尺
arcsin 0.273 - arcsin 0.815 就是答案了
有錯請指教